2sin^2x+5cosx+5=0

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Solution for 2sin^2x+5cosx+5=0 equation: 


Simplifying
2sin2x + 5cosx + 5 = 0

Reorder the terms:
5 + 5cosx + 2in2sx = 0

Solving
5 + 5cosx + 2in2sx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + 5cosx + -5 + 2in2sx = 0 + -5

Reorder the terms:
5 + -5 + 5cosx + 2in2sx = 0 + -5

Combine like terms: 5 + -5 = 0
0 + 5cosx + 2in2sx = 0 + -5
5cosx + 2in2sx = 0 + -5

Combine like terms: 0 + -5 = -5
5cosx + 2in2sx = -5

Add '-2in2sx' to each side of the equation.
5cosx + 2in2sx + -2in2sx = -5 + -2in2sx

Combine like terms: 2in2sx + -2in2sx = 0
5cosx + 0 = -5 + -2in2sx
5cosx = -5 + -2in2sx

Divide each side by '5osx'.
c = -1o-1s-1x-1 + -0.4in2o-1

Simplifying
c = -1o-1s-1x-1 + -0.4in2o-1

Reorder the terms:
c = -0.4in2o-1 + -1o-1s-1x-1

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